Posted: Tue 6th Mar 2007@20:21
This afternoon I realised I didn't listen properly in maths.
Without using the internet, and with only my mental arithmetic, I was trying to work out the following:
What is the direction in degrees from
Point AB to point CD
I was trying to work it out by taking C from A, and D from B
x = C-A
y = D-B
Then trying to work out where a circle would be intersected of you drew a line from its centre (at point 00) to point xy where the circle has a radius less than the greater of point x or y.
I think I may have made it too confusing! I am about to try to work it out using the internet now :(
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06 Mar 2007 @ 11:44
You trying to get the distance from (0,0) to point (x,y)?
http://mathforum.org/cgraph/cslope/mxplusb.html maybe
no link
07 Mar 2007 @ 12:49
what I meant was to find the direction. i.e a bearing from point (0,0) to point (x,y).
So for example, I could find the direction from my current point to a GPS location elsewhere.
http://stabeler.com/blog/
07 Mar 2007 @ 05:10
SOHCAHTOA ?
I used to love trig, then Flash sapped away all my skills through its shoddy actionscripting.
Sin = opp / hyp
Cos = adj / hyp
Tan = opp / adj
Give it some good ole math n plug it with the relevant function (Sin, Cos or Tan) to find the 'bearing' in degrees.
takes me back to being a wee nipper at school :D
Hope thats a push in the right direction?
http://zackbrown.co.uk
08 Mar 2007 @ 12:40
the answer is clearly \"your face\".
you aren\'t doing it right.
http://stuffedllama.com
08 Mar 2007 @ 09:40
I failed AS maths... then resat 2 modules and achieved a rather unspectacular 'E'
although, this is one of the (very) few bits i remember...
http://www.openhosting.co.uk
14 Mar 2007 @ 06:39
the angle = inverse tan ( (D-b)/(C-A))
no link
05 Nov 2007 @ 04:07
Worked out to be:
c^2 = a^2 + b^2
no link